(p' ise q') ise p neye denktir ?
(p' => q') => p
(Pvq')' v p = (p' ^ q) vP = ( p' ^ p) v ( q ^ p) = 0 v ( q ^ p) = q ^ p
p/q/P'/q'/(p'iseq')/(p'iseq')isep
1/1/0/0 /1 /0
1/0/0/1 /1 /0
0/1/1/0 /0 /0
0/0/1/1 /1 / 0
