Cevap :
[tex]\frac{x^2-y^2-2y-1}{x+y+1}=\frac{x^2-(y+1)^2}{x+y+1}=\frac{(x+y+1).(x-y-1)}{x+y+1}=x-y-1[/tex]
xkare-ykare-2y-1 arada kesir çizgisi var x+y+1
[tex]\frac{x^2-y^2-2y-1}{x+y+1}=\frac{x^2-(y+1)^2}{x+y+1}=\frac{(x+y+1).(x-y-1)}{x+y+1}=x-y-1[/tex]