2x3 – 5x2 – 3x + 2 = 2 please solve, ten points, in a rush thank you!! (:?
x3 + 64 = 0
x4 – 8x2 – 9 = 0
3 years ago
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Oliver Kahn
Best Answer - Chosen by Voters
1)
2x² – 5x² – 3x + 2 = 2
2x² – 5x² – 3x = 0
x(2x - 5x - 3) = 0
x= [5 ± √(25+24)]/4 = (5 ± 7)/4
x1 = 3
x2 = -1/2
so:
x(x+1/2)(x-3)
x(2x+1)(x-3)
2)
x³ + 64 = 0
64 = 4³
(x+4)(x²+4x+16)
3)
x^4 - 8x² - 9 = 0
x² = t
t² - 8t - 9 = 0
t = [8 ± √(64+36)]/2 =
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Other Answers (5)
kindrick...
2x3 – 5x2 – 3x + 2 = 2
2x3 – 5x2 – 3x = 0
x(2x^2 - 5x - 3) = 0
In the trinomial ac = 2(-3) = -6
Factors of -6 that add to -5 are +1 & -6
x(2x^2 + x - 6x - 3) = 0
x[x(2x + 1) - 3(2x + 1)] = 0
x(x - 3)(2x + 1) = 0
x = 0, 3, -1/2
3 years ago
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0% 0 Votes
Shahd
1) 2x3 – 5x2 – 3x + 2 = 2
x (2x^2 -5x -3) +2-2 =0
x = 0
x = 3
x = -1/2
2) x3 + 64 = 0
x^3 = -64
x = -4
3) x4 – 8x2 – 9 = 0
(x^2 - 9) (x^2+1)
x = 3, x = -3
3 years ago
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0% 0 Votes
fizixx
1) zero, 3, and -1/2
2) -4, 2 ± 2i√3
3) ±3, ±i
3 years ago
0% 0 Votes
2x(3)-5x(2)-3x+2=2
-6x(3)(2)+2=2
-6x(6)+2=2
-36x=0
x=0
