Cevap:
[tex]p(1) = {1}^{3} - 3 ({1})^{2} + a(1) + b = 4 \\ 1 - 3 + a + b = 4 \\ a + b = 6 \\ x + 1 = 0 \\ x = - 1 \\ p( - 1) = 8 \\ {( - 1)}^{3} - 3 {( - 1)}^{2} + a.( - 1) + b = 8 \\ - 1 - 3 - a + b = 8 \\ - a + b = 12 \\ a + b = 6 \\ \: toplarsak \: a \: lar \: gıder \\2 b = 18 \\ b = 9 \: a = - 3 \\ [/tex]
a.b=9.(-3)=-27