Cevap:
E
Adım adım açıklama:
Cevapta kullanılan formül:
[tex]sin^2x+cos^2x = 1[/tex]
Cevap:
[tex]\frac{-2cos^2x-sinx-(sin^2x+cos^2x)}{2sinx-3}.(sinx-1)\\ \\\frac{-3cos^2x-sin^2x-sinx}{2sinx-3}.(sinx-1)\\\\\frac{-3cos^2x-3sin^2x+2sin^2x-sinx}{2sinx-3}.(sinx-1)\\\\\frac{-3+2sin^2x-sinx}{2sinx-3}.(sinx-1)\\\\\frac{(2sinx-3).(sinx+1)}{2sinx-3}.(sinx-1)\\\\(sinx+1).(sinx-1) = sin^2x-1\\\\sin^2x-(sin^2x+cos^2x) = -cos^2x[/tex]
