Cevap:
[tex]\frac{2^{x+2}.3^{x-1} }{6^{x} } =\frac{2^{x+2}.3^{x-1} }{3^{x}.2^{x} } \\\\2^{x+2}.3^{x-1}.3^{-x}.2^{-x}=2^{x+2-x}.3^{x-1-x}\\\\2^{2} .3^{-1} =4.\frac{1}{3} =\frac{4}{3}[/tex]
