Cevap :

Math38

[tex]\dfrac{(1,2)^2-(0,8)^2}{(0,6).(0,4)} =\dfrac{(1,2-0,8).(1,2+0,8)}{(0,6).(0,4)} =\dfrac{(0,4).2}{(0,6).(0,4)} =\dfrac{2}{0,6}=\dfrac{2}{\dfrac{6}{10} }=\dfrac{2}{1}.\dfrac{10}{6}=\dfrac{10}{3}[/tex]

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